De Brogiles wavelength

$\lambda=\frac{h}{p}$

Alondra Juarez section 1E
Posts: 47
Joined: Fri Sep 29, 2017 7:03 am

De Brogiles wavelength

What is the wavelength of a neon atom traveling with a velocity of 4.34 X 10^3 m/s?

There was a similar question to this on test 2 but I wasn't sure how to do the problem would I convert the moles to atoms then convert grams to kilograms and once I got that it will give me the mass and finally use λ=h/mv in order to find the wavelength is that correct or am I missing something?

Sara Veerman-1H
Posts: 31
Joined: Fri Apr 06, 2018 11:05 am

Re: De Brogiles wavelength

Yes, I think you would have to use the molar mass and convert that to kg per unit(or atom). I don't know how else a person would be able to get the mass in order to plug it into the equation λ=h/mv.

octaviahuang1f
Posts: 30
Joined: Fri Apr 06, 2018 11:03 am

Re: De Brogiles wavelength

In addition to Sara's answer and pls correct me if I'm wrong:), since it's one atom of neon, the molar mass has to be converted using Avogadro's constant.

Yitzchak Jacobson 1F
Posts: 31
Joined: Wed Nov 22, 2017 3:00 am

Re: De Brogiles wavelength

I think the problem here is the method of getting the mass of the element to solve for the wavelength. De Broglie's equation would definitely solve for this by using lamda=h/mv. really hope this helps :)

Alexis Bravo 1D
Posts: 30
Joined: Tue Nov 14, 2017 3:01 am

Re: De Brogiles wavelength

You would use lambda= h/mv but would have to find the mass of the neon atom and plug that value into the equation.