## 1.55 part b

$\Delta p \Delta x\geq \frac{h}{4\pi }$

Husnia Safi - 1K
Posts: 33
Joined: Fri Sep 29, 2017 7:04 am

### 1.55 part b

In this question it is given that absorption occurs at 3600 cm^-1 and asks: what is the energy, in joules, that corresponds to that absorption?
It shows that the equation used is E = (c)(h)(v).
Im just curious as to where this equation came from?

Kara Justeson 1B
Posts: 31
Joined: Fri Apr 06, 2018 11:03 am

### Re: 1.55 part b

I might be wrong but I think the equation used for this problem was just E=hv. In part a you would find the frequency based on the given wavelength, and in part b, you would use the frequency you found in part a and just plug it into the equation E=hv.

Jaquelinne Rodriguez-Lopez 1L
Posts: 38
Joined: Mon Apr 09, 2018 1:38 pm
Been upvoted: 1 time

### Re: 1.55 part b

the question states they express energy in terms of v/c with units cm^-1. cm^-1 is basically 1/cm, right? so in order to get cm/1, c in v/c must be brought up to the numerator, thus v*c.