Photoelectric Problems

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Rogelio Bazan 1D
Posts: 64
Joined: Tue Nov 14, 2017 3:01 am

Photoelectric Problems

Postby Rogelio Bazan 1D » Mon May 07, 2018 12:30 am

Is the photoelectric effect just conceptual or is there actual computation for these equations? Do we just need to understand the graphs that depict the photoelectric effect and how this was revolutionary as a photon behaved as both a particle and a wave? Thank you-Roger.

annie_finneran_1K
Posts: 37
Joined: Fri Apr 06, 2018 11:02 am

Re: Photoelectric Problems

Postby annie_finneran_1K » Mon May 07, 2018 7:03 am

it is conceptual but also need to do problems involving equation

energy of photon = work function + KE of ekectron

1/2mv^2
E=hv
these are equations used for the calculations

Chem_Mod
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Re: Photoelectric Problems

Postby Chem_Mod » Mon May 07, 2018 3:13 pm

In addition to the photoelectric effect equation, you should be able to understand the parameters that can be manipulated. For example, if electrons are being expelled from the metal surface, what will happen if I increased intensity? How can I make the electrons be expelled at a higher velocity? Keep these questions in mind.

Elana Weingord 1C
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Joined: Fri Apr 06, 2018 11:05 am

Re: Photoelectric Problems

Postby Elana Weingord 1C » Mon May 07, 2018 7:03 pm

Does the photoelectric effect have to occur in a vacuum?

JooHyun Koh 1H
Posts: 22
Joined: Fri Apr 06, 2018 11:03 am

Re: Photoelectric Problems

Postby JooHyun Koh 1H » Mon May 07, 2018 11:39 pm

To answer the questions listed above...
1)What will happen if I increased intensity?
Intensity (the number of photons) has no effect on the velocity of the electron because the photoelectric effect illustrates a 1-to-1 interaction between photons and electrons of the metal. This is shown in the example where a high-intensity light of low frequency does not eject any electrons. The intensity of a light has no effect on the ejection of electrons.

2)How can I make the electrons be expelled at a higher velocity? Keep these questions in mind.
So, if intensity has no effect on the velocity of the electron, then what does? It would be to increase the energy of the incoming photon. Since the metal will always have a set work function (the energy required to eject an electron), increasing the electron increases the kinetic energy of the ejected photon since Energy of photon = work function + kinetic energy of the ejected electron.


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