## 9.15

Volume: $\Delta S = nR\ln \frac{V_{2}}{V_{1}}$
Temperature: $\Delta S = nC\ln \frac{T_{2}}{T_{1}}$

haleygamboa2E
Posts: 23
Joined: Fri Sep 25, 2015 3:00 am

### 9.15

Why is the answer for part (a) negative? (Besides that the heat of fusion is negative)

LinaLi2E
Posts: 22
Joined: Fri Sep 25, 2015 3:00 am

### Re: 9.15

Entropy is the measure of disorder. So "Low entropy means little disorder; high entropy means great disorder" (page 319 of the textbook). In part (a), you are asked to calculate the entropy change for freezing. When you freeze something, you are going from great disorder to little disorder thus you are going from high entropy to low entropy, resulting in the change of entropy to be negative.