Question about Uncertainty in Velocity  [ENDORSED]


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Alyssa Chan 3B
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Question about Uncertainty in Velocity

Postby Alyssa Chan 3B » Tue Oct 11, 2016 3:27 pm

When a problem says that ∆v is ± ____ m/s, why do you multiply the ∆v value by 2 when you're solving the uncertainty equation?

Ashley Van Belle 2B
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Re: Question about Uncertainty in Velocity  [ENDORSED]

Postby Ashley Van Belle 2B » Tue Oct 11, 2016 3:48 pm

∆v is change in velocity, and so the ± ____ m/s refers to the uncertainty of that value.

For example, say that the ∆v is 50 m/s ± 2. This means that there is an uncertainty in which your velocity could range from 48 to 52, because you added or subtracted 2 from 50. If you now notice, finding ∆v is the final velocity minus the initial velocity. 52 - 48 equals to 4.

Therefore, by simply multiplying your ± ____ m/s by 2, it is basically doing the same thing as finding the gap in which the velocity could lie.

I hope that this explanation helped and didn't confuse you!


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