Chapter 2 HW #93

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Janet Pham 1B
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Joined: Fri Jul 22, 2016 3:00 am

Chapter 2 HW #93

Postby Janet Pham 1B » Tue Oct 18, 2016 11:07 pm

The question shows 4 smaller atoms, labeled A, B, C, and D. The question says, "Below is pictured the reaction between an atom of sodium and an atom of chlorine. Identify each element and the ions formed and explain your reasoning." Atom A is shown to be smaller than Atom B, but the solution says that Atom A is Na and Atom B is Cl.

If atomic radius decreases as it goes to the right, wouldn't Atom A, the smaller atom, be Cl and Atom B, the bigger atom, be Na?

Vivian Wang 3J
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Re: Chapter 2 HW #93

Postby Vivian Wang 3J » Thu Oct 20, 2016 9:35 am


Since Na wants to lose that electron to make an octet, it will, becoming Na+.
Cl gains an electron with the bond, becoming Cl-.

It is the ionic bonding that causes them to change in atomic radius. If we were considering Na and Cl separately, the Na atom would have a greater atomic radius.

Paul Adkisson 1D
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Joined: Wed Sep 21, 2016 3:00 pm

Re: Chapter 2 HW #93

Postby Paul Adkisson 1D » Sun Dec 04, 2016 10:08 am

Also, it is certainly worth noting that 2.93 is one of the Solution Manual Errors, listed on Lavelle's website. The correct answer, contrary to the solution manual, is that Na > Cl, but Na+ < Cl-

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