HW 8.53

Josue_Marin_3I
Posts: 16
Joined: Wed Sep 21, 2016 2:56 pm

HW 8.53

Why is it that q(reaction) + q(calorimeter)=0 ?

Rachel_Smith_3D
Posts: 21
Joined: Wed Sep 21, 2016 2:58 pm

Re: HW 8.53

Since this is a bomb calorimeter, heat can't go in and out of the system (it's isolated). Therefore heat(q) of the entire system is 0. Therefore any heat lost by an exothermic reaction will warm up the calorimeter, or any heat absorbed by an endothermic reaction will come from the calorimeter and cool it down because there is nowhere else for this heat to go or come from. So the heat change of the reaction is equal and opposite to the heat change of the calorimeter, meaning their sum is 0.

Cobie_Allen_1H
Posts: 24
Joined: Wed Sep 21, 2016 2:56 pm

Re: HW 8.53

So essentially no heat leaves or enters the calorimeter, it is just that the heat is absorbed or given off within the isolated system? Please correct me if I am wrong, I was a little confused by that as well.

Myra_Zhan_2N
Posts: 25
Joined: Fri Jul 22, 2016 3:00 am

Re: HW 8.53

Another important thing to remember is that q will always equal 0 in an adiabatic process in a closed system. q cannot be negative or positive because no heat is added or removed.

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