## 14.35

$\Delta G^{\circ} = -nFE_{cell}^{\circ}$

Cowasjee_Sanaea_3E
Posts: 27
Joined: Fri Jul 22, 2016 3:00 am

### 14.35

Hi!
14.35: determine the equilibrium constants for the following reaction:

Mn (s) + Ti^2+ (aq) --> Mn^2+ (aq) + Ti (s)

I don't understand why when you solve for the cell potential it is negative?? I thought you always make it so that the cell potential is positive, even if that means reversing the cathode versus the anode?