## Steady State vs. Pre-Equilibrium Approach

$K = \frac{k_{forward}}{k_{reverse}}$

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Junghyuk_Park_1I
Posts: 34
Joined: Wed Sep 21, 2016 2:56 pm

### Steady State vs. Pre-Equilibrium Approach

What exactly are the differences between the steady-state and pre-Equilibrium approaches (and any others I may have excluded)? What are the differences conceptually and when would we use each? Thanks in advance!

Rachel Wile 2D
Posts: 49
Joined: Sat Jul 09, 2016 3:00 am

### Re: Steady State vs. Pre-Equilibrium Approach

When the methods are done correctly, you will get the same answer with either method. Lavelle said that we are not tested on the steady-state approximation, we use the pre-equilibrium method in this class. In the pre-equilibrium method, we assume that the reactants and intermediates are in equilibrium which is different than what is done in the steady state approach.

K Phelan 3D
Posts: 23
Joined: Wed Sep 21, 2016 2:59 pm

### Re: Steady State vs. Pre-Equilibrium Approach

And just to make sure it's really clear, we don't need to know how to do steady state.

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