2013 Final #4
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 40
- Joined: Wed Sep 21, 2016 2:59 pm
-
- Posts: 13
- Joined: Wed Sep 21, 2016 2:58 pm
Re: 2013 Final #4
I have a similar question how would we know the moles of electrons if we are not given the charges and Fe is a transition metal?
-
- Posts: 57
- Joined: Sat Jul 09, 2016 3:00 am
- Been upvoted: 1 time
Re: 2013 Final #4
2Fe(s) + 2H2O --> 2Fe(OH)2(s) + 4e-
pay attention to the charge for Fe as Fe is oxidized from 0 to +2
O2 + 4e- ----> 2Fe(OH)2(s)
pay attention to the charge for O as O is reduced from 0 to -2
pay attention to the charge for Fe as Fe is oxidized from 0 to +2
O2 + 4e- ----> 2Fe(OH)2(s)
pay attention to the charge for O as O is reduced from 0 to -2
-
- Posts: 23
- Joined: Wed Sep 21, 2016 3:00 pm
Re: 2013 Final #4
Wait, How would that work? The reduction reaction isn't balanced (Fe on products but not in reactants). I also had trouble determining n for this question.
-
- Posts: 11
- Joined: Wed Sep 21, 2016 2:57 pm
- Been upvoted: 1 time
Re: 2013 Final #4
So we would calculate the electron number from the changes in charges seen in the corresponding half reactions?
Return to “Balancing Redox Reactions”
Who is online
Users browsing this forum: No registered users and 14 guests