HW 8.45 (b)

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Luke Bricca 1H
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Joined: Fri Sep 29, 2017 7:06 am

HW 8.45 (b)

Postby Luke Bricca 1H » Sat Jan 13, 2018 11:14 am

For question 8.45 part b, why is the enthalpy value found divided by the 4 moles of CS2? I know that the standard enthalpy of formation is per one mole formed of the product, but in the reaction there are 4 moles of carbon used to form 4 moles of CS2, so shouldn't the ratio be 1:1 and therefore the 4 moles of CS2 not factored into the equation?

Curtis Tam 1J
Posts: 105
Joined: Thu Jul 13, 2017 3:00 am

Re: HW 8.45 (b)

Postby Curtis Tam 1J » Sat Jan 13, 2018 1:41 pm

The enthalpy change given is for every four moles of carbon reacted so that's why you must include that in your stoichiometric calculations :)


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