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Normally the calorimeter is not included in the equations and is assumed that it does not loose heat, but it could be in certain cases. However each of the heat constants have units attached to them. If you are using q=mCdeltaT, make sure the c you choose has mass, energy, and a unit of temperature in the units. Also make sure you use the corresponding units for the other variables in the equation.
Usually in problems where the presence of the calorimeter is taken into consideration, the problem will provide you with the heat capacity for the calorimeter, and not the specific heat capacity. This is actually easier as the equation you have to solve then becomes q= -(heat capacity of calorimeter)x(change in temperature of surroundings/calorimeter)
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