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When determining how stable a compound is, does a more negative standard Gibbs free energy of formation refer to the more stable compound? Say if you had two compounds, one that is more negative than the other. Would we classify the more negative compound as "more stable"?
I think that's true.
Yes, if the Gibbs standard free energy of one compound is more negative than another it is more stable because when it is in the form of its constituent elements it is less stable, meaning that when the reaction is spontaneous the formation of the product, which is more stable, is favored
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