Standard Molar Entropy Question

[Ryan Sydney Beyer 2B]

Arrange the following in order of increasing standard molar entropy: CHF3, CF4, CH3F, CH2F2

(all are in the gaseous phase)

The correct answer has CH3F < CH2F2 < CHF3 < CF4 but shouldn't have a higher standard molar entropy then since there are more ways to orientate the molecules?

[Curtis Wong 2D]

Remember that entropy also depends on the complexity of the molecule itself, so that also means the elements that it consists of. So in this case, F is more complex than H in terms of its atomic structure. It has more particles in its atom than H and each of those particles has more orientations possible. SO that's why CF4 has the highest entropy.

[Helen Shi 1J]

So the complexity of the molecule overrules positional disorder?

[Nancy Dinh 2J]

So the complexity of the molecule overrules positional disorder?

I think so. As far as my memory goes, I've only seen positional disorder come to play when T=0K.