## Work

isochoric/isometric: $\Delta V = 0$
isothermal: $\Delta T = 0$
isobaric: $\Delta P = 0$

Tiffany Cao 1D
Posts: 94
Joined: Fri Sep 29, 2017 7:03 am
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### Work

Am I right by saying that if volume does not change,if a gas expands in a vacuum, and if a gas undergoes free expansion, work is 0?

Michelle Chernyak 1J
Posts: 33
Joined: Fri Sep 29, 2017 7:06 am

### Re: Work

Yes you are correct. There s no work being done as a gas expands in a volume because there is no opposing force.

Posts: 60
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### Re: Work

Work done by expansion can be calculated by using w = -P * delta V. If delta V is zero, then there is no expansion occurring, and thus the overall work done is also zero. Note that under constant volume conditions, the change in internal energy of the system is given by qv and that the change in internal energy results from only the heat released by the reaction.

RohanGupta1G
Posts: 34
Joined: Sat Jul 22, 2017 3:00 am

### Re: Work

That is correct because the work done is a vacuum is 0 because there is no pressure or opposing force.

Patricia Macalalag 2E
Posts: 53
Joined: Sat Jul 22, 2017 3:00 am

### Re: Work

Yes, w=0.

Paula Dowdell 1F
Posts: 72
Joined: Tue Nov 15, 2016 3:00 am

### Re: Work

It's good to note that work is zero if applied force is zero (W=0 if F=0).