14.11d

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Kyra LeRoy 1E
Posts: 52
Joined: Sat Jul 22, 2017 3:00 am

14.11d

Postby Kyra LeRoy 1E » Sun Feb 18, 2018 3:50 pm

Can someone walk me through writing the half-equations and balanced equation for this problem?

Pt(s)|O2(g)|H+(aq)||OH-(aq)|O2(g)|Pt(s)

Aijun Zhang 1D
Posts: 53
Joined: Tue Oct 10, 2017 7:13 am

Re: 14.11d

Postby Aijun Zhang 1D » Sun Feb 18, 2018 4:56 pm

Pts are just inert electrodes.
The oxygen and H+ ions are on the anode side. Oxidation occurs anode side. So oxygen in the water will be oxidized into oxygen.

On the cathode side, reduction occurs. So O2 is reduced to OH-.


Then we need to balance the number of electrons on both sides. Since there are 4e- on both sides, we just need to add them up and subtract the same substance.
Then the balanced equation will be :


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