10 posts • Page 1 of 1
I don't really see a real need to convert to log, unless that makes the problem easier/more convenient. You should get the same answer either way if you're doing it right! Whatever's more convenient for you and your calculator/head, I suppose.
There is no need to convert ln into log, and this could cause an answer to be wrong if you ever need to get rid of ln. Since e^ln cancels out smoothly the finding the reaction constant or time is made easier. In short, stick with ln
Who is online
Users browsing this forum: No registered users and 0 guests