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When calculating the standard cell potential of a reaction, do we always flip the oxidation half reaction? I know that for galvanic cells, Ecell has to be greater than zero, so we flip the larger value, but I'm not sure about non-galvanic cells.
You want E to be positive because the reaction has to be spontaneous which only happens in galvanic cells. So, I believe that you have to flip the oxidation side if you are using that method of calculating E.
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