## 2008 Practice Final Q3D

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Andy Liao 1B
Posts: 52
Joined: Thu Jul 13, 2017 3:00 am

### 2008 Practice Final Q3D

I understand that the Nernst Equation is being used to solve for E in part (D). However, I don't understand how the answer key arrived at 1/(1*10^-16) for Q. Can someone please explain? Also, I'm sorry. The image automatically flipped when I posted it

Nicole Jacobs 1C
Posts: 59
Joined: Thu Jul 13, 2017 3:00 am

### Re: 2008 Practice Final Q3D

it is given that 1E-16 is the molarity of cu2+ in the question and since cu2+ is the reactant, you put its concentration in the denominator

Return to “Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)”

### Who is online

Users browsing this forum: No registered users and 0 guests