## test 2 #4

H-Atom ($E_{n}=-\frac{hR}{n^{2}}$)

danielruiz1G
Posts: 62
Joined: Fri Apr 06, 2018 11:04 am

### test 2 #4

On test 2 on question we had to find the energy difference but were not given then levels like n=? so how would we go about doing this?

Briana Lopez 4K
Posts: 44
Joined: Wed Nov 22, 2017 3:01 am

### Re: test 2 #4

I had trouble with that one too for the same reason. I assumed it was from n=1 to n=2, but wasn't sure.
The formula I used was the En= -hR/n^2 which I believe is the same as the V= R((1/n1^2)-(1/n2^2))

Chem_Mod
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### Re: test 2 #4

The energy lost from the transition is turned into the energy of the emitted photon. Thus, the energy difference is same as the energy of a photon. So, just needed to calculate E = hv.

EllenRenskoff-1C
Posts: 32
Joined: Fri Apr 06, 2018 11:04 am

### Re: test 2 #4

Just to clarify, is the equation En = -hR/ n^2 only used for calculating the change in energy levels for a hydrogen atom? I used this equation on the test, and I wanted to clarify that that was why this was wrong, since the question was asking about a multi-electron atom.

Tarek Abushamma
Posts: 30
Joined: Fri Apr 06, 2018 11:01 am

### Re: test 2 #4

I believe E=-hR/n^2 is only valid for hydrogen, yet this equation was not needed on the test.