Lone pairs on octahedral electron density

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Shivangi_2J
Posts: 65
Joined: Fri Sep 28, 2018 12:15 am

Lone pairs on octahedral electron density

Postby Shivangi_2J » Wed Nov 28, 2018 11:48 am

For all of the other VSEPR models, replacing an atom with a lone pair is done by taking away from the equatorial plane. But with the octahedral shape, an axial bond is replaced to form square pyramidal. Why is that so?

timschaeffer Dis 1J
Posts: 38
Joined: Fri Sep 28, 2018 12:18 am

Re: Lone pairs on octahedral electron density

Postby timschaeffer Dis 1J » Wed Nov 28, 2018 11:57 am

due to the symmetry of the octahedral shape, it doesn't matter where the first atom is removed from (axial or equatorial) because it will always result in a square pyramidal shape
Octahedral-3D-balls.png
Octahedral-3D-balls.png (23.37 KiB) Viewed 94 times

Cameron_Greenberg_3C
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am

Re: Lone pairs on octahedral electron density

Postby Cameron_Greenberg_3C » Fri Dec 07, 2018 4:57 pm

The axes are not relevant for an octahedral shaped molecule because the shape is the same no matter how the molecule is rotated. So any of the planes can have the four atoms with the two lone pairs above and below.

Ivan Tadeja 4B
Posts: 31
Joined: Fri Sep 28, 2018 12:28 am

Re: Lone pairs on octahedral electron density

Postby Ivan Tadeja 4B » Fri Dec 07, 2018 8:22 pm

With every other VSEPR shape, 1 removed molecule removed will affect the configuration in different ways with respect to the one removed, thus resulting in different possible bond angles in some. With octahedral, no matter which one is removed, the result will always be the same.


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