2E.19b (7th Edition)

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2E.19b (7th Edition)

Postby hannahdaijo_4H » Thu Nov 29, 2018 6:01 pm

For the lewis structure of (CH3)2Be, where beryllium is connecting the two methyl groups, does that connecting atom need to have a complete octet or not/is Be just an exception to the rule where it can exist with only four valence electrons?

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Re: 2E.19b (7th Edition)

Postby 804991762_4A » Thu Nov 29, 2018 6:24 pm

It does not need a full octet since its an exception to the rule. As long as it has 2 bonds it's happy.

Nina Do 4L
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Re: 2E.19b (7th Edition)

Postby Nina Do 4L » Thu Nov 29, 2018 6:31 pm

Be does not need to fulfill its octet because it is the first four elements on the periodic table and the same exceptions go for Be as it does for H, He, and Li.

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