## Labeling hybridization in Test 3

$sp, sp^{2}, sp^{3}, dsp^{3}, d^{2}sp^{3}$

Rian Montagh 2K
Posts: 60
Joined: Fri Sep 28, 2018 12:15 am

### Labeling hybridization in Test 3

For test 3 number 3c., I was asked to write the hybridization a nitrogen atom that was bonded to a carbon and two hydrogens, and had a lone pair. I thought that it would have a tetrahedral formation with the four e- densities, so I labeled it sp3 and it was wrong. What's the correct hybridization and why?

Henry Krasner 1C
Posts: 64
Joined: Fri Sep 28, 2018 12:15 am

### Re: Labeling hybridization in Test 3

Because of the 3 bonds and one lone pair, although the geometry is tetrahedral, the actual shape would be trigonal pyramidal, because of the lone pair. This would result in angles slightly less than 109.5 degrees.

Alana Sur 3B
Posts: 61
Joined: Fri Sep 28, 2018 12:25 am

### Re: Labeling hybridization in Test 3

Your hybridization was correct - 4 regions of electron density should be an sp3 hybridization