2nd order
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2nd order
Can someone explain why a second order graph has a positive slope? Does this mean that the concentration is increasing?
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Re: 2nd order
The second order graph has nothing to do with the concentration, but rather the second derivative.
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Re: 2nd order
The y-axis is the inverse of the concentration of A. Thus, the slope shows that as time increases, the inverse of [A] increases (not [A] itself).
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Re: 2nd order
Since the graph is 1/A v time and when you integrate that you'll get 1/[A] = kt + 1/[A]o, and when you plot 1/[A] against t you'll get a positive slope because k is positive
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