## T, Ea, and A's effect on K

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

Hai-Lin Yeh 1J
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### T, Ea, and A's effect on K

Can someone explain the effect of T, Ea, and A's effect on K from both a conceptual approach and a mathematical approach using the equation? Also, in the textbook, they state: "the higher the activation energy, the stronger is the temperature dependence of the rate constant". Can someone explain this? Thanks!

Celine Cheng 1H
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Joined: Fri Sep 28, 2018 12:21 am
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### Re: T, Ea, and A's effect on K

Regarding your 2nd question about Ea and temperature dependence, when looking at lnk = -Ea/(RT) + lnA, we compared -Ea/R to m (slope) and T to x (y = mx + c). So the larger the Ea, the larger the slope and the greater the effect T has on k. (k changes more drastically w larger slope)

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