15.63 (6th addition)

Arrhenius Equation:

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melodyzaki2E
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Joined: Fri Sep 28, 2018 12:18 am

15.63 (6th addition)

Postby melodyzaki2E » Fri Mar 15, 2019 2:54 pm

The rate constant of the reaction between CO2 and OH in aqueous solution to give the HCO3- ion is 1.5 *10^10 L/mol*s at 25 C. Determine the rate constant at blood temperature (37 C), given that the activation energy for the reaction is 38 kJmol-1.

Karyn Nguyen 1K
Posts: 72
Joined: Fri Apr 06, 2018 11:04 am

Re: 15.63 (6th edition)

Postby Karyn Nguyen 1K » Fri Mar 15, 2019 4:39 pm

I'm getting stuck on this question too. I was looking at the solution and I was wondering where 0.59 came from.

Karyn Nguyen 1K
Posts: 72
Joined: Fri Apr 06, 2018 11:04 am

Re: 15.63 (6th edition)

Postby Karyn Nguyen 1K » Fri Mar 15, 2019 4:51 pm

Karyn Nguyen 1K wrote:I'm getting stuck on this question too. I was looking at the solution and I was wondering where 0.59 came from.


This is the solution:

ln(k'/k) = (38 kJ/mol)/(0.08314 kJ/molK)


Maddy Mackenzie
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Joined: Fri Sep 28, 2018 12:22 am
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Re: 15.63 (6th addition)

Postby Maddy Mackenzie » Fri Mar 15, 2019 7:11 pm

Can anyone explain where the .59 comes from? Additionally, isn't the equation ln (k2/K1) = -Ea/R (1/T2 - 1/T1)? So why would the temperature corresponding to T2 come second in the solutions maual?


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