(Polar molecules, Non-polar molecules, etc.)
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starting from a pentagonal bipyramidal if you turn 3 into lone pairs where would you put the third lone pair? would it still be on the equatorial plane? or would it need to be an axial because of the lone pair repulsion?
I learned in a step up that you continue to put it on the equatorial plane so that the trigonal part of the structure is now gone. The shape becomes linear, with the two bonded pairs as far as possible, which is 180 degrees.
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