[Fe(CN)6]4-

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KDang_1D
Posts: 127
Joined: Fri Aug 30, 2019 12:15 am
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[Fe(CN)6]4-

Postby KDang_1D » Sat Nov 23, 2019 8:58 am

In lecture, Dr. Lavelle used the example [Fe(CN)6]4-:

a. How is CN a ligand? Unless it's CN-, it would have an unpaired electron and wouldn't be able to form a coordinate covalent bond?
b. Why is the charge 4-?

CMaduno_1L
Posts: 102
Joined: Wed Sep 18, 2019 12:18 am

Re: [Fe(CN)6]4-

Postby CMaduno_1L » Sat Nov 23, 2019 11:39 am

I believe it is CN-, meaning it can form the coordinate covalent bond. However, I'm not exactly sure why the total charge is 4-.

Claire Lo 3C
Posts: 55
Joined: Sat Aug 17, 2019 12:18 am

Re: [Fe(CN)6]4-

Postby Claire Lo 3C » Sat Nov 23, 2019 12:27 pm

The total charge is given so that you can calculate the charge of the Fe ion. In this case, since the total charge of 4-, and CN has a charge of -1, the charge of the Fe ion is +2

WYacob_2C
Posts: 102
Joined: Sat Jul 20, 2019 12:16 am

Re: [Fe(CN)6]4-

Postby WYacob_2C » Sat Nov 23, 2019 1:03 pm

The CN- ions are considered the ligands, and these ions provide the electron pairs that form bonds to Fe2+

Joowon Seo 3A
Posts: 100
Joined: Sat Aug 24, 2019 12:17 am

Re: [Fe(CN)6]4-

Postby Joowon Seo 3A » Sat Nov 23, 2019 6:04 pm

CN binds to the Fe ion. The Fe ion is the central TM. By definition CN is a ligand. The charge is -4 because the Fe ion is +2. Since there are 6 CN- it becomes:
+2-6=-4

MBouwman_4A
Posts: 40
Joined: Wed Sep 18, 2019 12:21 am

Re: [Fe(CN)6]4-

Postby MBouwman_4A » Sat Nov 23, 2019 6:09 pm

Since CN has a -1 charge, the -4 overall charge is given to calculate the charge of iron (Fe), which is +2.


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