Explanation of overall charge of ion

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105194078
Posts: 52
Joined: Thu Sep 19, 2019 12:17 am

Explanation of overall charge of ion

Postby 105194078 » Sat Dec 07, 2019 11:26 am

Can someone explain to me how this overall charge of this ion is 4....
[Pt(H2NCH2CH2NH2)2Cl2]Cl2

Amanda Ung 4D
Posts: 50
Joined: Thu Jul 25, 2019 12:17 am

Re: Explanation of overall charge of ion

Postby Amanda Ung 4D » Sat Dec 07, 2019 12:39 pm

[Pt(en)2Cl2]Cl2 is a coordination compound and coordination compounds are neutral. Because chloride has a charge of -1 and there are 2 in the compound, we can conclude that the complex ion [Pt(en)2Cl2] has an overall charge of +2. The oxidation number of platinum would be +4 because, as previously stated, chloride has a charge of -1 and there are 2 in the complex ion. It seems like the question might have been asking to figure out the charge of the metal cation rather than the whole complex ion (if the answer stated is 4). You can figure out the oxidation number of metal atoms using this formula:
x(# of metal atom) + Σ(# of ligand)(charge of ligand) = overall charge of the complex ion
x = oxidation number (charge) of metal atom

kristi le 2F
Posts: 102
Joined: Thu Jul 11, 2019 12:15 am

Re: Explanation of overall charge of ion

Postby kristi le 2F » Sat Dec 07, 2019 10:22 pm

Each Cl inside the bracket is one negative. But also there are 2 Cl, each one negative, for a combination of -4. So, Pt must have an oxidation number of 4 for the total complex to be neutral.


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