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Postby 705121606 » Fri Feb 28, 2020 7:22 pm

When we write the cell diagram for the following reaction
2NO3- (aq) + 8H+(aq) + 6Hg(l) --> 3Hg2 2+ (aq) + 2NO(g) + 4H2O(l)

how come the diagram does not include a solid on the anode side?
Hg(l)|Hg2 2+ (aq)||No3-(aq)| H+(aq)|NO(g)|Pt(s)

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Re: 6m5a

Postby CynthiaLy4F » Fri Feb 28, 2020 11:08 pm

The diagram does not include a solid in this case because Hg(l) is being used as the electrode on the anode side.

Brian J Cheng 1I
Posts: 115
Joined: Thu Jul 11, 2019 12:15 am

Re: 6m5a

Postby Brian J Cheng 1I » Sat Feb 29, 2020 12:32 pm

Weird setup, but keep in mind there are exceptions to the rules we are taught. Here is one of them :) doubt we will see this on our exam though as it is almost eerily specific

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