stoichiometric coefficients
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stoichiometric coefficients
For the reaction 3/2 O2 -> O3, why do we use the stoichiometric coefficient of 3/2? Would it still be correct if we multiply both sides by 2, or is that not the simplest form of the equation?
Re: stoichiometric coefficients
the reaction is correct either way. You can multiply by 2 if you want.
Re: stoichiometric coefficients
Both are correct as mentioned above, and I don't think you'd lose points for having either. Typically we haven't really left coefficients in fractions, at least on exams and tests.
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Re: stoichiometric coefficients
It's correct whether in fraction or whole number form, because the equations we use relate the two in ratio form anyways.
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Re: stoichiometric coefficients
The reason it was in fraction form was because the first step of the reaction wanted to be written to get exactly one mole of product just to make it simpler. Therefore, to make this happen, there needed to be 1/2(O2) as a reactant. If you had started with 1 mole O2 then you would end up with 2 moles O3 in the end.
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Re: stoichiometric coefficients
Either way works, but the reaction is written with the fraction so that the coefficient of the product is one.
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Re: stoichiometric coefficients
Sometimes you want one of the species in your equation to be 1 mol, which is why other species have fractions as coefficents.
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Re: stoichiometric coefficients
Either way is correct, but if you wanted to answer a question with one mol of O3, then you can use the reaction with 3/2 to make it simpler.
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Re: stoichiometric coefficients
Using a fraction is useful if you only want the product to have 1 mol in your equations.
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Re: stoichiometric coefficients
This shows the standard reaction where you want to get exactly one mole of product, which means we use fractions for the reactants if needed.
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